Question

the length and breath of a room are 8 m and 6 m. a cat runs along the four walls and finally along a digonal order to catch a rat. how much distance is totally covered by the cat.
.

Answer 1

length = 8m
breadth=6m
perimeter = 2(l+b)
               =2(8+6)
               =2(14)
               =28m .
diagonal divides the rectangle shaped room into two equal right-angled triangles
  So, the diagonal will be the hypotenuse of the right-angled triangle .
      We know that (hypotenuse)²=(side)²+(side)²
     So, (hypotenuse)²=(8)²+(6)² 
                               =64+36
                               =100
         hypotenuse=√100=10m
   therefore , the total distance covered by the cat = 28m+10m=38m

Answer 2

Perimeter of rectangle is 2lb and total length of 4 walls is 28m
diagonal of this is sq root of 8^2+6^2 which is 10 m and hence the total distance ran by rat is 38 m.