Question

The length and bredth of a park ate in the ratio 3:2and its perameter is 300m a path 3 meter wide runs inside it along its boundry find the cost of levelling the path at rupees 3 per m

Answer 1

Ratio of length and breadth of a park=3:2

Let the length be 3x and breadth be 2x.

Perimeter of the park=300m

2(l+b)=300

3x+2x=300/2

5x=150

x=150/5

x=30

So,the length of the park=3×30=90m

Breadth of the park=2×30=60m

Area of the park=l×b sq.units

=90×60

=5400m^2

Width of the park=3m

Now,area of the park without width=(l-2(3))×(b-2(3))

=(90-6)×(60-6)

=84×54

=4536m^2

Area of the width=area of park-area of park without boundary

=864m^2

Cost of leveling per sq.m=₹3

Cost of leveling the path=3×864

=₹2592