Question

the length and diagonal of a rhombus are 30 and 40 cm respectively find the sides of the Rhombus​

Answer 1

Answer:25 cm

Step-by-step explanation:

Since, diagonal of a rhombus bisect each other at right angles and a O.

So, Doa = 90° and AO = 15 cm

DO = 20 cm.

In triangle DOA l, O = 90° DO= 20 cm

AO= 15 cm by Pythagoras theorem

(DA)^2 = OA^2 + DO^2

DA^2 = 20^2 + 15^2

= 400 + 225

DA^2 = 625

DA = 25 Cm

Hope it helps

Answer 2

Step-by-step explanation:

D1=30

D2=40

A/C to Pythagoras theorem,

side of rhombus =√15^2++√20^2

√225+400

√625=25

perimeter = 4×side

= 4 ×25= 100