Math, asked by tomarsachin678, 1 year ago

The length and height of a cuboid tank are 150 cm 120 CM and 110 CM respectively the tank has 129600 cm cube of water in it 100 porous brakes is having dimension 27 cm * 10 cm *10 cm are place in the tank and calculate the rise in the water level of the tank if each break observe 1/10 of its own volume

Answers

Answered by shree1571
1

Data regarding volume of water in the tank = 129,600 cm^3 or 1,296,000 cm³ ??

 

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Volume of the tank =  150 * 120 * 110  cm³  = 1, 980, 000 cm³

base area of the tank =  150 * 120 =  18, 000 cm²

volume of water in the tank = 129, 600  cm³ 

filled height of water in the tank =   129, 600 / 18 000 = 7. 2 cm

      

Volume of the porous bricks = 20 * 10 * 10 = 2, 000 cm³  each

Amount of water absorbed by each brick = 1/10 * 2, 000 = 200 cm³

Amount of water absorbed by all 100 bricks =  20, 000 cm³ 

Volume of water remaining = 129, 600 - 20, 000 cm³  = 109, 600 cm³

Now volume occupied by the bricks = 100 * 2, 000 = 200, 000 cm³

Total volume of bricks + water = 309, 600 cm³

Height of water in the tank now  = total volume / base area

           = 309, 600 / 18, 000  = 17.2 cm

Rise in the level of water = 17.2 - 7.2 = 10 cm

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