Question

The length and perimeter of a rectangle are (4x^2 + 3x - 5) units and (2x^3 + x - 3) units, respectively. Find the breadth of the rectangle.

Answer 1

Answer:

3 units

Step-by-step explanation:

Perimeter of rectangle=                       (4x^2 + 3x - 5) units and (2x^3 + x - 3)unit

So length=                                           4*2=8+ -15=           -7

therefore, breadth=                             2*3=6 +-3=           3

so perimeter=                                     -1

Answer 2

Answer:

Step-by-step explanation:

Length of rectangle=$4 x^{2} +3x-5$

Perimeter =$2x^{3}+x-3$

PERIMETER =2×(L+)

ATQ

$\implies 2 (4 x^{2} +3x-5+B)=2x^{3} +x-3\\ \implies 8x^{2} +6x-10+2B=2x^{3} +x-3\\\implies 2B=2x^{3} +x-3-(8x^{2} +6x-10\\\implies 2B=2x^{3} +x-3-8x^{2} +6x-10\\\implies 2B=2x^{3} +7x-13-8x^{2} \\\implies B=\frac{2x^{3} +7x-13-8x^{2}}{2}$

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