Question

The length and the breadth of a rectangle are 12 cm and 9 cm respectively. Find
the height of a triangle whose base is 9 cm and whose area is one-third that of
rectangle.​

Answer 1

Answer:

8 cm

Step-by-step explanation:

Length = 12 cm

Breadth = 9 cm

Area of rectangle = length*breadth

        = 12*9 = 108 cm^2

Now, Area of triangle = 1/3 of area of rectangle

                                   = [1/3]*108 = 36 cm^2

Base of triangle = 9 cm

Area of triangle = [1/2]*base*height

36 = [1/2]*9*height

height = [36*2]/9

height = 8 cm

Answer 2

Answer:

Area of rectangle = 12 × 9 = 108 cm^2

Since , area of triangle = 1/3rd area of

Rectangle

So,

Area of triangle = 108 / 3 = 36 cm^2

Since altitude of a triangle divides it into two parts of equal area ,

Area of half triangle = 36/2 = 18 cm^2

Lenght of half base = 9/2 = 4.5 cm

Let height of triangle = h

Area of triangle = 1/2 × base × height

18 = 1/2 × 4.5 × h

h = 18 × 2 / 4.5

h = 36 / 4.5

h = 8 cm

Height of the triangle = 8 cm

Hope it helps you!

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