Question

The length and the breadth of a rectangle are (2x + 5) cm and (2x - 1) cm respectively. The area of the rectangle is three times the area of a square of sides (x + 1) cm.
(1) Form an equation in x and show that it
reduces to x2+ 2x - 8 = 0.
(ii) Solve the equation x2 + 2x - 8 = 0.
(iii) Find the perimeter of the rectangle.​

Answer 1

Hey buddy this is your answer

the length and breadth of a rectangle are %282x%2B5%29cm and %28+2x-1%29cm respectively, the area of rectangle is
%282x%2B5%29%2A%28+2x-1%29
the area of square %28x%2B1%29cm is %28x%2B1%29%5E2
the area of rectangle is three times the area of square %28x%2B1%29cm, we have
%282x%2B5%29%2A%28+2x-1%29=3%28x%2B1%29%5E2......simplify
%282x%2B5%29%2A%28+2x-1%29=3%28x%2B1%29%5E2
4x%5E2+%2B+8x+-+5=3%28x%5E2%2B2x%2B1%29
4x%5E2+%2B+8x+-+5=3x%5E2%2B6x%2B3
4x%5E2+%2B+8x+-+5-3x%5E2-6x-3=0

x%5E2+%2B+2x+-+8=0 => shows that is reduces to x%5E2%2B2x-8=0




Hope it helps
Thanks
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