the length and the breadth of a rectangle are in ratio 5 ratio 3 if the area of the rectangle is 75 square cm find first length and breadth of the rectangle second perimeter of the rectangle third length of its diagonal
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Since the ratio of length and breadth of the given rectangle is 3:2, let the length and breadth be 3x and 2x respectively.
Thus 3x * 2x = 38400 (as area of rectangle = length * breadth and area = 38400)
Hence 6x^2 = 38400 => x * x = 6400 and therefore x = 80.
As a result, we can conclude that the length = 3x = 240 and breadth = 2x = 160.
Thus the perimeter of the rectangle = 2 * (length + breadth) = 2 * (240 + 160) = 2 * 400 = 800.
Thus 3x * 2x = 38400 (as area of rectangle = length * breadth and area = 38400)
Hence 6x^2 = 38400 => x * x = 6400 and therefore x = 80.
As a result, we can conclude that the length = 3x = 240 and breadth = 2x = 160.
Thus the perimeter of the rectangle = 2 * (length + breadth) = 2 * (240 + 160) = 2 * 400 = 800.
In the quest area is 75. you have taken 38400?
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Thus 3x * 2x = 38400 (as area of rectangle = length * breadth and area = 38400)
Hence 6x^2 = 38400 => x * x = 6400 and therefore x = 80.
As a result, we can conclude that the length = 3x = 240 and breadth = 2x = 160.
Thus the perimeter of the rectangle = 2 * (length + breadth) = 2 * (240 + 160) = 2 * 400 = 800.