The length and the breadth of a rectangular field are 40 m and 30 m, respectively. It is surround its outside by a uniformly broad path of 2.5 m. What is the area of the path in square metre?
Answers
Step-by-step explanation:
Given:
Length and Breadth of the rectangular field is 40m and 30 m respectively.
Width of Park which is outside the field is 2.5 m
To Find:
What is the area of path ?
Solution: Let ABCD is a rectangular park inside the path.
★ Area of rectangle ABCD = Length x Breadth
\small\implies{\sf }⟹ Area of ABCD = 40 x 30
\small\implies{\sf }⟹ 1200 m²
★ In rectangle EFGH ★
Length = EF = AB + ( 2.5 + 2.5) = 40+5 = 45 m
Breadth = FG = BC + (2.5 + 2.5) = 30+5 = 35 m
∴ Area of rectangle EFGH = Length x Breadth = EF x FG
\small\implies{\sf }⟹ Area of EFGH = 45 x 35
\small\implies{\sf }⟹ 1575 m²
Now we have to find the area of path which lies between the area of EFGH and ABCD. So after subtracting the area of ABCD from EFGH we will get the area of the path .
\small\implies{\sf }⟹ Area of path = Ar.( EFGH – ABCD ) m²
\small\implies{\sf }⟹ ( 1575 – 1200 ) m²
\small\implies{\sf }⟹ 375 m²
Hence, The area of path is 375 m².
Answer:
The area of the path is 375 m² .
Step-by-step explanation:
The length and the breadth of the rectangular field are 40 m and 30 m respectively.
the area of the field is (40 × 30 ) = 1200 m²
the length of the field along with the path is ( 40 + 2×2.5 ) = 45 m
the breadth of the field along with the path is ( 30 + 2×2.5 ) = 35 m
Hence , the area of the field along with the path is ( 45 × 35 ) = 1575 m²
then , the area of the path is ( 1575 - 1200 ) = 375 m²