The length and the breadth of a rectangular field are in the ratio 4:3 .its area is 6912m.sq ,find the cost of fencing the field at 2.50per metre?
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Answered by
1
Answer:
total cost = 840
Step-by-step explanation:
let length= 4x and breadth= 3x
then area 4x * 3x = 6912
or, 12x2 = 6912
or, x2 = 576
or, x = 24
then, length= 96mtr and breadth= 72mtr
perimeter= 2(96+72)=336 mtr
total cost/mtr= 336*2.50 = 840/-
Answered by
3
★
- Ratio[Length to Breadth] ➠ 4:3
- Area ➠ 6912 m²
- Cost of fencing per meter ➠ ₹2.50
★
- Total cost of fencing the field.
★
First, let us find the length and the breadth:
➜ Let the common multiple be x
➢ Area = Length breadth
➥ 6912 = 4x 3x
➥ 6912 = 12x²
➥ x² =
➥ x² = 576
➥ x =
➥ x = 24 m
➥ Therefore,
✦ Length = 4x = 4 24 = 96 m
✦ Breadth = 3x = 3 24 = 72 m
➢ Perimeter = 2(Length + Breadth)
➥ 2(96 + 72)
➥ 2 168
➥ 336 m
➢ Total cost of fencing = Cost of fencing per m Perimeter
➥ 2.50 336
➥ ₹840
Therefore the total cost of fencing the field is ₹840.
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