Question

The length and the breadth of a rectangular field are in the ratio 4:3 .its area is 6912m.sq ,find the cost of fencing the field at 2.50per metre?​

Answer 1

Answer:

total cost = 840

Step-by-step explanation:

let length= 4x and breadth= 3x

then area 4x * 3x = 6912

or, 12x2 = 6912

or, x2 = 576

or, x = 24

then, length= 96mtr and breadth= 72mtr

perimeter= 2(96+72)=336 mtr

total cost/mtr= 336*2.50 = 840/-

Answer 2

★$\bf{\underline{Given::}}$

• Ratio[Length to Breadth] ➠ 4:3
• Area ➠ 6912 m²
• Cost of fencing per meter ➠ ₹2.50

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★$\bf{\underline{To\:Find::}}$

• Total cost of fencing the field.

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★$\bf{\underline{Sol^{n}::}}$

First, let us find the length and the breadth:

➜ Let the common multiple be x

➢ Area = Length $\times$ breadth

➥ 6912 = 4x $\times$ 3x

➥ 6912 = 12x²

➥ x² = $\dfrac{6912}{12}$

➥ x² = 576

➥ x = $\sqrt{576}$

➥ x = 24 m

➥ Therefore,

   ✦ Length = 4x = 4 $\times$ 24 = 96 m

   ✦ Breadth = 3x = 3 $\times$ 24 = 72 m

➢ Perimeter = 2(Length + Breadth)

➥ 2(96 + 72)

➥ 2 $\times$ 168

➥ 336 m

➢ Total cost of fencing = Cost of fencing per m $\times$ Perimeter

➥ 2.50 $\times$ 336

➥ ₹840

Therefore the total cost of fencing the field is ₹840.

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