the length and the breadth of a rectangular field are in the ratio 7:4. the cost of the fencing the field at 25 rupees per metre is 3 3300 rupees. find the dimensions of the field.
Answers
Answer:
24 m
Step-by-step explanation:
The total cost fencing of the field = Rs.3300 Rate of fencing = Rupees 25 per meter
Perimeter of the field = Total cost /Rate
= 3300/25
= 132 m
Let the length and breadth of the field be 7x and 4x, then Perimeter of the field = 2(7x + 4x)m
= 2(11x)
= 22x
.. 22x = 132
x = 132/22
x = 6
Hence, the length of the field is 7x
= 7 x 6
= 42 m
Breadth of the field = 4x
= 4 x 6
= 24 m
Answer:
- Ratio of sides of field = 7 : 4
- Rate of fencing = Rs. 25 per metre
- Cost of fencing = Rs. 3300
- Dimensions of the field = ?
Let the Length and Breadth of the rectangular field be 7n and 4n respectively.
☢ According to the Question :
⇢ Cost of fencing = Perimeter × Rate of fencing
⇢ Rs. 3300 = 2(L + B) × Rs. 25 per metre
⇢ Rs. 3300/Rs. 25 per metre = 2(L + B)
⇢ 132 metre = 2(L + B)
⇢ 132 metre = 2(7n + 4n)
⇢ 132 metre = 2 × 11n
⇢ 132 metre = 22n
⇢ 132 metre/22 = n
⇢ n = 6 metre
⠀⠀⠀⠀⠀───────────────
☢ Dimensions of the field :
◗ Length = 7n = 7(6 m) = 42 metre
◗ Breadth = 4n = 4(6 m) = 24 metre