Question

the length and the breadth of a rectangular field are in the ratio 5:3 if it's perimeter is 128m,find it's demension of the field​

Answer 1

Answer:Let the length be '5x' and breadth be '3x'

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=128

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=1282*8x = 1282∗8x=128

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=1282*8x = 1282∗8x=1288x=648x=64

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=1282*8x = 1282∗8x=1288x=648x=64x = 8x=8

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=1282*8x = 1282∗8x=1288x=648x=64x = 8x=8length = 5x = 40 m

Let the length be '5x' and breadth be '3x'2(5x + 3x) = 1282(5x+3x)=1282*8x = 1282∗8x=1288x=648x=64x = 8x=8length = 5x = 40 mbreadth = 3x = 24 m

Answer 2

Answer:

let the length and the breadth be 5x and 3x

perimeter = 128

.i.e, 128 = 2(l+b)

128 = 2( 5x +3x)

128= 10x+ 6x

16x = 128

x = 128/16

x = 8

therefore the length = 5x

= 5× 8= 40

and the breadth = 3x

= 3× 8 = 24