Question

The length and the breadth of a
rectangular park are 65 m and 45 m,
respectively. Two cross roads, each 5
m wide, run at right angles through the
centre and parallel to its sides. Find the

cost of roads at the rate of rupees 25
per meter square.​

Answer 1

Answer:

hope it helps

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m  

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the  

center of the park 5×5 = 225 sq.m  

area of roads = area of first road +area of second cross road−common area

                                           

=(350+225)−25

=575−25

=550sqm

​  

 

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answer 2

Step-by-step explanation:

Given :-

Length of park = 65

Breadth of park = 45 m

Two cross roads, each 5m wide, run at right angles through thecentre and parallel to its sides

To Find :-

Total cost

SoluTion :-

Firstly the road are running parallel by 5 m

Length :-

\tt \: Length = 65 \times 5Length=65×5

\tt \: Length \: = 325 \: mLength=325m

Breadth :-

\tt \: Breadth = 45 \times 5Breadth=45×5

\tt \: Breadth = 225 \: mBreadth=225m

Area of both sides

\tt \: 325 + 225 - 25325+225−25

\tt \: 550 - 25550−25

\tt \: 525 {m}^{2} 525m

2

Now,

Let's find total cost

Total cost = 25 × 525

\mathfrak \pink{Total cost = 13125}Totalcost=13125