the length and the breadth of a rectangular park are in the ratio 8:5 .A path 1.5 wide runing all around the outside of parakaha an area of 594 sq m find the dimensions of the park
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area of rectangle park = 8x * 5x
=40x²
length of outside = 8x + 2 * 2.5 = 8x + 5
breadth of outside = 5x + 2 * 2.5 = 5x + 5
area of out side park = (8x+5)*(5x+5)
=40x² + 65x + 25
area of the park = 40x² - 40x² + 65x + 25
594 = 65x + 25
65x = 594 - 25
@@
=40x²
length of outside = 8x + 2 * 2.5 = 8x + 5
breadth of outside = 5x + 2 * 2.5 = 5x + 5
area of out side park = (8x+5)*(5x+5)
=40x² + 65x + 25
area of the park = 40x² - 40x² + 65x + 25
594 = 65x + 25
65x = 594 - 25
@@
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The length and the breadth of a rectangular park are in the ratio 8:5 .A path 1.5 wide runing all around the outside of park an area of 594 sq m find the dimensions of the park
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Wwwarshpundir2003 · Ambitious
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area of rectangle park = 8x * 5x
=40x²
length of outside = 8x + 2 * 2.5 = 8x + 5
breadth of outside = 5x + 2 * 2.5 = 5x + 5
area of out side park = (8x+5)*(5x+5)
=40x² + 65x + 25
area of the park = 40x² - 40x² + 65x + 25
594 = 65x + 25
65x = 594 - 25
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