Math, asked by 11RahulKumar11, 1 year ago

The length and the breath of a park are in the ratio 3 : 2 and its perimeter is 500 m. A path of 3 m wide runs beside it along the boundary. Find the cost of gravelling the path at the rate of 20 rupee per square metre.

Answers

Answered by DevilPriest
0
First find area of inner rectangle and then deduct it from the bigger one.
Attachments:

11RahulKumar11: but answer is not correct sir
DevilPriest: oh yeah
11RahulKumar11: this question answer is 17568
Answered by student65
4
☆let the length = 3x
let the breadth = 2x
perimeter = 500m
so 2 (2x+3x)= 500m
so x = 500/10=50
so length = 3×50=150m
breadth = 2×50=100m
☆area of park =150×100=15000sq.m
☆length of path = 150+3×2=150+6=156m
breadth of path = 100+3×2=100+6=106m
total area of park = 156×106= 16536msq.
☆so area of path = total area-area of park
= 16536-15000
= 1536sq.m
☆cost of gravelling the path = 20 rupees per square.m
so cost = 20×1536= 30720rupees

Mark it as a it as a brainliest

11RahulKumar11: but answer is not correct sir
11RahulKumar11: answer is coming 17568
student65: U r telling the digit is that area of path or cost
11RahulKumar11: cost
Similar questions