The length and the breath of a park are in the ratio 3 : 2 and its perimeter is 500 m. A path of 3 m wide runs beside it along the boundary. Find the cost of gravelling the path at the rate of 20 rupee per square metre.
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First find area of inner rectangle and then deduct it from the bigger one.
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11RahulKumar11:
but answer is not correct sir
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☆let the length = 3x
let the breadth = 2x
perimeter = 500m
so 2 (2x+3x)= 500m
so x = 500/10=50
so length = 3×50=150m
breadth = 2×50=100m
☆area of park =150×100=15000sq.m
☆length of path = 150+3×2=150+6=156m
breadth of path = 100+3×2=100+6=106m
total area of park = 156×106= 16536msq.
☆so area of path = total area-area of park
= 16536-15000
= 1536sq.m
☆cost of gravelling the path = 20 rupees per square.m
so cost = 20×1536= 30720rupees
Mark it as a it as a brainliest
let the breadth = 2x
perimeter = 500m
so 2 (2x+3x)= 500m
so x = 500/10=50
so length = 3×50=150m
breadth = 2×50=100m
☆area of park =150×100=15000sq.m
☆length of path = 150+3×2=150+6=156m
breadth of path = 100+3×2=100+6=106m
total area of park = 156×106= 16536msq.
☆so area of path = total area-area of park
= 16536-15000
= 1536sq.m
☆cost of gravelling the path = 20 rupees per square.m
so cost = 20×1536= 30720rupees
Mark it as a it as a brainliest
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