Question

The length and width of a rectangle are consecutive odd integers and perimeter is 168 CM. Find the length and width of the rectangle?? ​

Answer 1

Let one width be x.

So,

length = (x+2) {consecutive odd integers}

Perimeter = 168 cm

According to condition,

2{x+(x+2)} = 168

or, 2(2x+2) = 168

or, 4x+4 = 168

or, 4x = 168-4

or, 4x = 164

or, x = 164/4

or, x = 41

So, width = x = 41 cm.

Length = (x+2) = (41+2) cm = 43 cm.

Hence, the length and width of the rectangle are 41 cm and 43 cm respectively.

Hope this helps you to get to your answer.

Answer 2

$\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• The length and width of a rectangle are consecutive odd numbers
• perimeter = 168 cm

___________________

$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Length of rectangle = ??
• Breadth of rectangle = ??

______________________

$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

• Let the length be x
• Breadth = x + 2

⠀⠀⠀⠀

$\sf{\red{\boxed{\bold{perimeter = 2 ( l + b)}}}}$

⠀⠀⠀⠀

: $\sf\implies\:{\bold{ 2 ( x + x + 2 )= 168 }}$

⠀⠀

: $\sf\implies\:{\bold{ 2x + 2 = 84}}$

⠀⠀⠀⠀

: $\sf\implies\:{\bold{ 2x = 84 - 2 }}$

⠀⠀⠀⠀

: $\sf\implies\:{\bold{ 2x = 82 }}$

⠀⠀⠀⠀

: $\sf\implies\:{\bold{ x = 41 }}$

⠀⠀⠀⠀

$\sf{\pink{\boxed{\bold{length = 41}}}}$

⠀⠀⠀⠀

Breadth = x + 2

⠀⠀⠀⠀

Breadth = 41 + 2

⠀⠀⠀⠀

Breadth = 43

⠀⠀⠀⠀

$\sf{\pink{\boxed{\bold{breadth = 43cm}}}}$

______________________

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Length = 41cm and breadth = 43cm