Question

The length and width of a rectangle are consecutive odd integers and the perimeter is 168cm . Find the length and width of the triangle.

Answer 1

this is my solution...... hope it helps

Answer 2

The length and width of the rectangle are "41 cm and 43 cm".

Step-by-step explanation:

We have,

The perimeter of a rectangle = 168cm

Let length(l) $= x$ and breadth(b) $=x+2$

To find, the length and width of the triangle = ?

We know that,

The perimeter of rectangle =2(Length + Breadth)

⇒$2[x+(x+2)]=168$

⇒$x+(x+2)=\dfrac{168}{2} =84$

⇒$2x+2=84$

⇒$2x = 84-2 =82$

⇒$x=\dfrac{82}{2} =41$

∴ x + 2 = 41 + 2 = 43 cm

Hence, the length and width of the rectangle are 41 cm and 43 cm.