Question

The length and width of a rectangle are consecutive odd integers. Find the length and the width of a rectangle if its perimeter is 56 units.

Answer 1

Answer:

Step-by-step explanation:

Let the two consecutive odd integers be n and n+2

Perimeter of rectangle=56 units

2(l+b)= 56 units-------- eq 1

Let us assume that n= length and n+2= breadth

Substituting in eq 1,

2(n+n+2)= 56

4n+4=56

4n=56-4

4n=52

n=52/4

n=13units

n+2=13+2=15 units

Therefore, length =13 units and

Breadth =15units

Answer 2

let length = x units.
so breadth = x+2units.
perimeter given = 56 units.
peri. of rect. = 2( l + b )
56 = 2{ x + ( x+2) }
56 = 2{ x+ x + 2}
56 =2{ 2x + 2 }
56/2 = 2x+2
28-2 = 2x
26/2 = x
x = 13 units.
length = 13 units and
breadth = 13 + 2 = 15 units.