Question

the length and width of a rectangle hall is 20m and 9m respectively. find how many square tiles of size 3 dcm will be required for flooring the hall? ​

Answer 1

Step-by-step explanation:

length of rectangle is equal to 20 metre and breadth of rectangle is equal to 9 m area of rectang =L×B

area of rectangle is equal to 20 into 9 =180msq

No of tiles=180×10÷0.3 =600m

Answer 2

Step-by-step explanation:

Given:-

The length and width of a rectangle hall is 20m and 9m respectively.

To find:-

Find how many square tiles of size 3 dcm will be required for flooring the hall?

Solution:-

Length of the rectangular hall = 20 m

We know that 1 m = 10 dcm

Length of the rectangular hall= 20×10 = 200 dcm

Width of the rectangular hall = 9m = 9×10 = 90 dcm

Area of a rectangle = length × breadth sq.units

Area of the given rectangular hall =

200×90 sq.dcm

=>18000 sq.dcm

Size of the square tile = 3 dcm

Area of a square = side × side sq.units

Area of the given square = 3×3 = 9 sq.dcm

Now,

Let the number of square tiles required be "n"

n×area of the each tile = area of the rectangular hall

=>n×9 = 1800

=>n = 1800/9

=>n=200

Number of tiles = 200

Answer:-

Required number of square tiles flooring the rectangular hall is 200

Used formulae:-

• 1 m = 10 dcm
• Area of a rectangle = length × breadth sq.units
• Area of a square = side × side sq.units