The length and width of a rectangular field is in ratio 3:4. Its area is 6912 sq.cm. What its dimensions?
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Let
Length, L = 3k
Width ,W = 4k
Area = 3k * 4k
6912 = 12k^2
k^2 = 576
k = 24
Therefore dimensions are :
L = 3k = 72
W = 4k = 96
Length, L = 3k
Width ,W = 4k
Area = 3k * 4k
6912 = 12k^2
k^2 = 576
k = 24
Therefore dimensions are :
L = 3k = 72
W = 4k = 96
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