the length and width of a rectangular field is of the ratio 3:4 . lts area is 6912 sq.cm. Find it's dimensions
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let length be x and breadth be y
ATQ
x/y = 3/4
x = 3y/4
And ATGC
xy = 6912
3y²/4 = 6912
3y² = 27648
y² = 9216
y = 96
as x = 3y/4
x = 3 x 96 / 4 = 72
ATQ
x/y = 3/4
x = 3y/4
And ATGC
xy = 6912
3y²/4 = 6912
3y² = 27648
y² = 9216
y = 96
as x = 3y/4
x = 3 x 96 / 4 = 72
AngelaM:
thank you
Answered by
0
let length of the rectangular field be 3x and width of the rectangular field be 4x.
and we know, the area of rectangle = l+b
so, 6912= 3x+4x
6912=7x
7x=6912
x=6912/7
x=987.4
length=2962.2 cm
width= 3949.6 cm
i hope u find this answer helpful
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and we know, the area of rectangle = l+b
so, 6912= 3x+4x
6912=7x
7x=6912
x=6912/7
x=987.4
length=2962.2 cm
width= 3949.6 cm
i hope u find this answer helpful
mark it as brainilist
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