Question

The length and width of the rectangle are 12 cm and 9 cm. Find its area and perimeter.​

Answer 1

Answer:

Area= 108cm.

Perimeter= 41cm.

Step-by-step explanation:

Area of rectangle= length×Breadth

=12×9= 108cm.

Perimeter of rectangle= 2(Lenghth+Breadth)

=2(12+9)

=2×21= 41cm.

Answer 2

$\bf\pink{QuestioN:-}$

The length and width of the rectangle are 12 cm and 9 cm. Find its area and perimeter.​

$\bf\green{AnsweR:-}$

✧GiveN✧:-

In the given rectangle,

Length = 12 cm

Breadth = 9 cm

✧To FinD✧:-

The area and perimeter of the given rectangle.

✧SolutioN✧:-

The length and width of the rectangle is already known , ie,

Length = 12 cm

Breadth =9 cm

As we know,

The formulae applied here are,

⟿ Area of a rectangle = Length × Breadth

⟿ Perimeter of a rectangle = 2(Length + Breadth)

♡Area!♡

$:\implies\bf{Area=Length\times{B}readth}$

$:\implies\bf{Area=12\times9}$

$:\implies\bf{Area=108~cm^2}$

♡Perimeter!♡

$:\implies\bf{Perimeter=2\times(L+B)}$

$:\implies\bf{Perimeter=2\times(12+9)}$

$:\implies\bf{Perimeter=2\times21}$

$:\implies\bf{Perimeter=42~cm}$

Happy Learning!☆