Math, asked by shankar123999p8qy9y, 1 year ago

the length,bread,and height of a hall are 10m,8m, and 6m, respectively. the hall has two doors of area 2m×1.5m and three windows of area 1.5m×1m. find the cost of painting the walls (only the walls)at the rate of rupees 180per square metre

Answers

Answered by atul103
3
Hi friend!!

Here is your Answer
__________________________

Given that
length of the hall= 10 m
breadth of the hall= 8m
height of the hall = 6m

now find the area of the four walls

= 2h (l+b)
= 2×6(10+8)
= 12×18
= 216 m^2

Now the 2 doors where
which is length & breadth 2× 1.5
area of two doors = 2×{ 3 }
= 6 m^2

area of the window
= 1.5m × 1m
= 1.5 m^2
there are three windows
so
= 3×1.5 m^2
= 4.5 m^2

Now area of the wall = area of four wall - ( area of doors+ area of windows)

= 216 - 10.5
= 205.5 m^2

now
the cost of painting the walls

= 205.5× 180
= 36990 Rs

hope it's helpful
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