Question

The length, breadth and height of a bungalow are 8m, 6m, 7m respectively. The length, breadth of door are 5m, 4m respectively. Two windows of length 4m and breadth 1m are
there. The four walls are to be painted internally with the rate of 20 sq.m. Find the cost of painting the bungalow.​

Answer 1

Answer:

Given,

Length of room =6m

Breadth of room =5m

Height of room =3.5m

So, Area of four walls =2(+b)×h=2(6+5)×3.5=77m

2

Area of 2 doors and 3 windows =(2×1.1×2+3×1.5×1.4)=(44+6.3)m

2

=10.7m

2

Area of ceiling =l×b=6×5=30m

2

Thus, total area for whitewashing =(77−10.7+30)m

2

=96.3m

2

Hence, the cost of whitewashing =Rs.(96.3×5.30)=Rs.510.39

Answer 2

Answer :-

Length = 8m

Breadth = 6m

Height = 7m

Length Of door = 5m

breadth of door = 4m

2 windows length = 4m

2 windows breadth = 1m

4 walls to be painted internally with the rate of 20 sq.m

_____________________

Area of 4 walls = 2 (l+b) h

2 (8+6) 7

2 (14) 7

196

Area = 196 m²

_______________________

Area of door = L x B

5 X 4

20

Area = 20 m²

_______________________

Area of 2 windows = L x B

8 X 1

8

Area = 8 m²

_______________________

Total area painted = area of walls - (area of door + area of windows)

196 - (20+8)

196 - (28)

196-28

168

area painted = 168 m²

Rate of painting bungalow = Rs 20

168 x 20

3360

Rs 3360

hope it helps