Question

The length, breadth and height of a bungalow are 8m, 6m, 7m respectively. The length, breadth of door are 5m, 4m respectively. Two windows of length 4m and breadth 1m are
there. The four walls are to be painted internally with the rate of 20 sq.m. Find the cost of painting the bungalow.​

Answer 1

Given :

• Length, breadth, and height of a bungalow = 8m, 6m, 7m.
• The length, breadth of the door are 5m, 4m.
• Two windows of length 4m and breadth 1m.

To find :

• The four walls are to be painted internally at a rate of 20 sq.m.

Solution :

⇒ Total Area of Bungalow = (l × b) + h

= (8 × 6) + 7

= (48) + 7

= 55 m²

⇒ Area of Door = l × b

= 5 × 4

= 20 m²

⇒ Area of Windows = l × b

= 4 × 1

= 4 m²

Area of two windows = 4 × 2

                                   = 8 m²

⇒ Total Area to be painted = 55 - (20 + 8)

= 55 - (28)

= 27 m²

Cost of painting = 27 × 20

                           = Rs. 540

• Therefore, the cost of painting the bungalow is Rs. 540.

Answer 2

Answer :-

Length = 8m

Breadth = 6m

Height = 7m

Length Of door = 5m

breadth of door = 4m

2 windows length = 4m

2 windows breadth = 1m

4 walls to be painted internally with the rate of 20 sq.m

_____________________

Area of 4 walls = 2 (l+b) h

2 (8+6) 7

2 (14) 7

196

Area = 196 m²

_______________________

Area of door = L x B

5 X 4

20

Area = 20 m²

_______________________

Area of 2 windows = L x B

8 X 1

8

Area = 8 m²

_______________________

Total area painted = area of walls - (area of door + area of windows)

196 - (20+8)

196 - (28)

196-28

168

area painted = 168 m²

Rate of painting bungalow = Rs 20

168 x 20

3360

Rs 3360

hope it helps