Question

The length, breadth, and height of a cubical water tank are 7m, 6m and 15m respectively. if8400 litres of water is pumped out of the water tank, find the fall in the water level of in the water and tank?​

Answer 1

this question answer

Answer 2

$\textbf{\huge\underline{\underline\red{solution} : - }} \\ \\ \bold{\underline\purple{here \: we \: know}} \\ \\ \red{1.} \bold \blue{ \: length \: (l)\: of \: cuboidal \:water \: tank \: is \: 7 \: m .} \\ \red{2.} \bold \blue{ \: breadth \:( b)\: of \: cuboidal \: water\: tank \: is \: 6 \: m.} \\ \red{3.} \bold \blue{ \: height \: (h)\: of \: cuboidal \: water \: tank \: is \: 15 \: m.} \\ \red{4.} \bold \blue{ \: 8400 \: litres \: of \: water \: pumped \: out \: from } \\ \: \: \: \: \bold \blue{water \: tank.} \\ \\ \underline\bold\red{ \: To \: find \: \: fall \: of \: water \: level \: in \: water \: tank.} \\ \\ \underline\bold\red{ \: we \: use \: formula : - } \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{l \times b\times h} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{7 \times 6\times 15} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{630 \: {m}^{3} } \\ \\ \underline\bold\red{ \: we \: know \: } \: \: \fbox\bold\pink{ \: 1 \: {m}^{3} = \: 1000 \: litre \: } \\ \\ \underline\bold\blue{ \: hence} \\ \\ \bold\purple{\:630 \: {m}^{3} = 630 \times 1000 = 630000 \: litre} \\ \\ \underline \bold\blue{now} \\ \\ \underline\bold\purple{fall \: of \: water \: level \: in \: water \: tank} \\ = \: \: \: \bold\blue{(water \: in \: water \: tank \:) } \\ \: \: \: - \bold\orange{ \: (\: 8400 \: litre water \: pumped \: out)} \\ \\ \bold\purple{fall \: of \: water \: level... =( 630000 \: - 8400 \:) litre} \\ \\ \bold\purple{fall \: of \: water \: level... = 621600 \: litre} \\ \\ </p><p> \underline \bold \red{Hence \blue{\: 621600 \: litre \: }water \: remain \: in \:water \:} \\ \underline \bold \red{ tank \: after\blue { \: 8400 \: litre \: } \: of \: water \: pumped \: out.}$