The length, breadth and height of a cubiod are are in the ratio 6:5:4. if the surface area of the cubiod is 592 m^2. find
(i) length, breadth and height of the cubiod
(ii) Volume of the cubiod
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3
surface area=2(ab + bc + ca)
592 =2(6x*5x+5x*4x+4x*6x)
592 =2(30x+20x+24x)
592 = 2(74x)
592 =148x
x=592/148
x=4
length=24,bredth=20,hieght=16
volume of cuboid=l * b * h
=24*20*16
=7680 meter cube
592 =2(6x*5x+5x*4x+4x*6x)
592 =2(30x+20x+24x)
592 = 2(74x)
592 =148x
x=592/148
x=4
length=24,bredth=20,hieght=16
volume of cuboid=l * b * h
=24*20*16
=7680 meter cube
Answered by
6
Ans:-
(i) Length= 12 m. Breadth = 10 m. Height= 8m.
(ii) Volume of the Cuboid = 960 m^3.
HOPE IT HELPS. HAVE A GOOD DAY. AND DON'T FORGET TO MARK AS BRAINLIEST.
(i) Length= 12 m. Breadth = 10 m. Height= 8m.
(ii) Volume of the Cuboid = 960 m^3.
HOPE IT HELPS. HAVE A GOOD DAY. AND DON'T FORGET TO MARK AS BRAINLIEST.
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