The length, breadth and height of a cuboid are in the ratio 7:6:5 . If the surface area of the cuboid is
1962cm², find it's dimensions. Also find the volume of the cuboid.
Answers
The length, breadth and height of a cuboid are in the ratio 7:6:5 . If the surface area of the cuboid is 1926cm², find it's dimensions. Also find the volume of the cuboid.
Given:-
Surface area of a cuboid = 1926cm²
Ratio of dimensions = 7:6:5
Let,
The length of the cuboid be 7x
The breadth of a cuboid be 6x
The height of a cuboid be 5x
We know,
From Question,
Surface area of cuboid = 1926
2(lb+lh+bh) = 1926
=>2[7x•6x+7x•5x+6x•5x] = 1926
=>2[42x+35x+30x] = 1926
=> 2(107x). = 1926
=> 214x = 1926
=> x =
=> x = 9
Therefore, substituting the value of x
Length = 7 × 9 = 63cm
Breadth = 6 × 9 = 54cm
Height = 5 × 9 = 45cm
We have,
Volume= 63×54×45
= 153090cm³
Length = 7 × 9 = 63cm
Breadth = 6 × 9 = 54cm
Height = 5 × 9 = 45cm
Volume= 153090cm³
The Length , Breadth & Height of a Cuboid are in the ratio 7:6:5 . If the surface area of the Cuboid is 1926 cm² , find it's dimensions . Also find the volume of the Cuboid .
Let the ratios of 7x , 6x & 5x .
So ,
- Length (l) = 7x
- Breadth (b) = 6x
- Height (h) = 5x
Now ,
Using the Formula for finding TSA
So ,
★ Dimensions : 21cm × 18cm × 15cm .
★ Volume of the Cuboid = 5670 cm³ .