Question

The length, breadth and height of a cuboid are (log 125 + log8), (log 1000-log 10) and log 10 respectively. Find the total surface area of the cuboid.​

Answer 1

Answer:

Volume of the cuboid = 22 square units

Step-by-step explanation:

L = log 125 + log8 = log 5³ + log 2³

Using $loga^b=bloga$ and $loga+logb=log(ab)$

Thus,

L = 3 log 10

B = log 1000-log 10 = log 10³ - log 10 = 2 log 10

H = log 10

So,

Total surface area = 2 (lb + bh + hl) = 2 ( (3 log 10 × 2 log 10) + (2 log 10 × log 10) + (log 10 × 3 log 10) ) = 22 × (log 10)²

log 10 = 1

So,

Volume of the cuboid = 22 square units