Question

the length breadth and height of a cuboidal water tank are 7 m, 6 m and 15 m respectively if 8400 litres of water is pumped out of the water tank find the fall in the water level in the water tank?

Answer 1

it's answer is 20 cm
hope its correct

Answer 2

$\textbf{\huge\underline{\underline\red{solution} : - }} \\ \\ \bold{\underline\purple{here \: we \: know}} \\ \\ \red{1.} \bold \blue{ \: length \: (l)\: of \: cuboidal \:water \: tank \: is \: 7 \: m .} \\ \red{2.} \bold \blue{ \: breadth \:( b)\: of \: cuboidal \: water\: tank \: is \: 6 \: m.} \\ \red{3.} \bold \blue{ \: height \: (h)\: of \: cuboidal \: water \: tank \: is \: 15 \: m.} \\ \red{4.} \bold \blue{ \: 8400 \: litres \: of \: water \: pumped \: out \: from } \\ \: \: \: \: \bold \blue{water \: tank.} \\ \\ \underline\bold\red{ \: To \: find \: \: fall \: of \: water \: level \: in \: water \: tank.} \\ \\ \underline\bold\red{ \: we \: use \: formula : - } \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{l \times b\times h} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{7 \times 6\times 15} \\ \\ = > \underline\bold\purple{volume \: of \: cuboid } = \bold\red{630 \: {m}^{3} } \\ \\ \underline\bold\red{ \: we \: know \: } \: \: \fbox\bold\pink{ \: 1 \: {m}^{3} = \: 1000 \: litre \: } \\ \\ \underline\bold\blue{ \: hence} \\ \\ \bold\purple{\:630 \: {m}^{3} = 630 \times 1000 = 630000 \: litre} \\ \\ \underline \bold\blue{now} \\ \\ \underline\bold\purple{fall \: of \: water \: level \: in \: water \: tank} \\ = \: \: \: \bold\blue{(water \: in \: water \: tank \:) } \\ \: \: \: - \bold\orange{ \: (\: 8400 \: litre water \: pumped \: out)} \\ \\ \bold\purple{fall \: of \: water \: level... =( 630000 \: - 8400 \:) litre} \\ \\ \bold\purple{fall \: of \: water \: level... = 621600 \: litre} \\ \\ </p><p> \underline \bold \red{Hence \blue{\: 621600 \: litre \: }water \: remain \: in \:water \:} \\ \underline \bold \red{ tank \: after\blue { \: 8400 \: litre \: } \: of \: water \: pumped \: out.}$