The length, breadth and height of a hall are 16m,10m and 6m respectively. It has two doors measuring 2m×1.5m each and four windows measuring 2m×2m each. Find the cost of white washing all the four walls and the ceiling of hall at the rate of ₹5 per m².
Answers
Make sure the given data is correct. If it is,
Answer:
Rs 1450
Step-by-step explanation:
Area of 4 walls = 2(l + b)h
Given, l = 16m, b = 10m, h = 6 m
∴ Area of 4 walls = 2(16+10)6
= 312 m²
But this area includes the area of two doors and four windows, which must be subtracted.
Area of 2 doors = 2 [length x breadth]
= 2(2 x 1.5) = 6 m²
Area of 4 windows = 4 [2 x 2 ]
= 16 m²
Area to be white washed = 312 - 16 - 6 = 290 m²
∴ Cost of painting = rate x area
= Rs 5 x 290
= Rs 1450
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GIVEN
- Length Of a Hall = 16m
- Breadth Of a Hall = 10m
- Height Of a Hall = 6m
- Four walls
- Four windows
- Two doors
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Formula = 2 X (length + breadth) Height
Area of 4 walls :-
2(16+10) 6
2(26) 6
52 X 6
= 312
Area = 312 m²
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Now, find area of Windows
Area of 4 windows :-
4 (2X 2)
4 (4)
= 16 m2
Area = 16 m²
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Area Of 2 doors :-
2 (2 X 1.5)
2 (3)
= 6
Area = 6 m²
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cost of white washing
312 - 16 - 6
312 - 22
= 290
= 290 m²
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ceiling of hall at the rate of ₹5 per m².
= Rate X Area
= 5 X 290
= 1450
Rs 1450
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hope it helps