Math, asked by pawanpars5142, 11 months ago

The length breadth and height of a Hall are 25m 15 m 5m respectively. Find the cost for renovating it's floor and 4wall at the rate of rs 80 per sq m

Answers

Answered by trishakumari
49

Answer:

total surface area = 2(lb+ bh +hl)

=2(25*15+15*5+5*25)

=1150m^2

surface area of celling=l*b

=25*15

= 375

area of 4 walls and floor= 1150- 375

= 775

cost of renovating= 775*80

= 62000

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Answered by priyanachimuthupriya
4

Answer

62,000

step by step explanation

Here, length (1) = 25 m, breadth (b) =15 m. height (h) = 5 m. Area of four walls = LSA of cuboid

= 2(1+b)xh

= 2(25 +15)x5

=80×5=400 m²

Area of the floor = 1xb

= 25x15

= 375 m²

Total renovating area of the hall

(Area of four walls + Area of the floor)

= (400 +375) m² = 775 m²

Therefore, cost of renovating at the rate of 380 per m² = 80×775

= 62,000

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