Math, asked by manisawant143, 3 months ago

The length , breadth and height of a metallic parallelepiped is 16 cm , 1 1 cm and 10 cm respectively . It was melted and cast into discs . The diameter and thickness of each dics was 4 cm and 0.2 cm respectively . what was the number of discs fromed ?[π = 22/7 ] Complete the following activity and find the answer.​

Answers

Answered by mmnaveenkumar26
1

Answer:

700

Step-by-step explanation:

volume=16×11×10=1760cm^3

volume of each disc=22/7R^2H

=22/7×2×2×0.2

=17.6/7cm^3

no of discs can be formed=1760/17.6/7

=1760×7/17.6=7×100

=700

Answered by overachiever04
3

Answer:

since the solid was recast into the another solid so probably the amount of the matter which is melted and reconstructed into a new solid is not gonna change so the volume is going to be equal so we can easily substitute the values and put them on lhs and RHS of the equal to and get the answer

volume of paralellpipe = l × b × h

16 × 11 × 10 = 1760cm³

volume of disc = 1/3 × 22/7 × 4 × 4 × 2/10

(4=radius,0.2=>2/10, pie = 22/7)

volume of 1 disc = 352/105

if we divide volume of paralellpipe by volume of 1 disc we get the number of discs

=>1760 × 105 / 352

=>( 352 × 5 => 1760) so it simply gets cut and we get

=>2 × 105

=210

so the number of discs will be 210

hope this helped you mate =)

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