Question

The length, breadth and height of a rectangular block are found to be 15.12 ± 0.02 cm, 7.86 ± 0.01 cm and 4.16 ± 0.02 cm, respectively. Compute the percentage error in the volume of the block.

Help!

Answer 1

Answer:

= 0.74 %

Explanation:

◾ Lenght = 15.12 ± 0.02

◾ Breadth = 7.86 ± 0.01

◾ Height = 4.16 4 ± 0.02

$\sf{ \%_{error} = \left(\dfrac{\delta L}{L} + \dfrac{\delta B}{B} + \dfrac{\delta H}{H} \right) \times 100}$

$\sf{ \%_{error} = \left(\dfrac{\delta 0.02}{15.12} + \dfrac{\delta 0.01}{7.86} + \dfrac{\delta 0.02}{4.16} \right) \times 100}$

$\sf{  = \left( 0.001323 + 0.001272 + 0.004807\right) \times 100}$

= 0.74 %