The length breadth and height of a rectangular solid are in the ratio of 653 find the length breadth and height of the solid if its total surface area is it true 2268
Answers
Answer:
Length = 18√2 Cm
Breadth = 15√2 Cm
Height = 9 √2 Cm
Step-by-step explanation:
Given---> Ratio of length , breadth , and height of the solid is 6:5:3 and Total surface area is 2268 m² .
To find---> Value of length , breadth and height of the solid.
Solution---> ATQ, ratio of length , breadth , and height 6:5:3.
Let , length of rectangular solid = 6x
Breadth of rectangular solid = 5x
Height of rectangular solid = 3x
Total surface area = 2 ( lb + bh + lh )
= 2 ( 6x × 5x + 5x × 3x + 6x × 3x )
= 2 ( 30 x² + 15 x² + 18 x² )
= 2 ( 63 x² )
= 126 x²
ATQ,
Total Surface area of rectangular solid = 2268
=> 126 x² = 2268
=> x² = 2268 / 126
=> x² = 18
=> x = √18
=> x = 3 √2
Length = 6x
= 6 ( 3√2 )
= 18 √2 Cm
Breadth = 5x
= 5 ( 3√2 )
= 15 √2 Cm
Height = 3 x
= 3 ( 3√2 )
= 9√2 Cm
#Answerwithquality
#BAL
Answer:
Step-by-step explanation:
Given---> Ratio of length , breadth , and height of the solid is 6:5:3 and Total surface area is 2268 m² .
To find---> Value of length , breadth and height of the solid.
Solution---> ATQ, ratio of length , breadth , and height 6:5:3.
Let , length of rectangular solid = 6x
Breadth of rectangular solid = 5x
Height of rectangular solid = 3x
Total surface area = 2 ( lb + bh + lh )
= 2 ( 6x × 5x + 5x × 3x + 6x × 3x )
= 2 ( 30 x² + 15 x² + 18 x² )
= 2 ( 63 x² )
= 126 x²
ATQ,
Total Surface area of rectangular solid = 2268
=> 126 x² = 2268
=> x² = 2268 / 126
=> x² = 18
=> x = √18
=> x = 3 √2
Length = 6x
= 6 ( 3√2 )
= 18 √2 Cm
Breadth = 5x
= 5 ( 3√2 )
= 15 √2 Cm
Height = 3 x
= 3 ( 3√2 )
= 9√2 Cm