the length breadth and height of a rectangular solid at in the ratio 5:4:2 . if its total surface area is 1216 cm square .find the volume of the solid .
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let the length=5x,breadth=4x and height be 2x
tsa of cuboid=1216cm^2
2(lb+bh+hl)=1216cm^2
2(5x×4x+4x×2x+2x×5x)=1216
2(20x^2+8x^2+10x^2)=1216
2(38x^2)=1216
76x^2=1216
x^2=1216/76
x^2=16
x=sqrt 16
x=4
then length=5×4=20cm
breadth=4×4=16cm
height=2×4=8cm
tsa of cuboid=1216cm^2
2(lb+bh+hl)=1216cm^2
2(5x×4x+4x×2x+2x×5x)=1216
2(20x^2+8x^2+10x^2)=1216
2(38x^2)=1216
76x^2=1216
x^2=1216/76
x^2=16
x=sqrt 16
x=4
then length=5×4=20cm
breadth=4×4=16cm
height=2×4=8cm
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