Question

The length , breadth and height of a
room are 12m, 10m,and 9m
respectively.find the area of four
walls of the room​

Answer 1

Answer:

396

Step-by-step explanation:

lateral surface area of cuboid= 2h(l+b)

because it doesn't add top and bottom so we find out lateral surface area.

2*9(12+10)

18*22

396

Answer 2

Given :

• length = 12 m
• Breadth = 10 m
• Height = 9 m

To find :

• Area of four walls

Solution :

• The area of four walls of the room is given by :

$\underline{\boxed{\sf area \: of \: four \: walls = 2(l + b)h}}$

Where ,

• l = length
• b = breadth
• h = height

•°• Area of four walls of room = 2 ( 12 + 10) 9

= 2 × 22 × 9

= 44 × 9

= 396 m² .

Hence the area of four walls of the room is 396 m².

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• The shape of the room is mostly cuboid . Cuboid is a 3d figure of rectangle .

• The area of four walls of the cuboid = 2(l + b) h
• Since , perimeter of rectangle = 2(l + b) , area of four walls = Perimeter of one face × height .

• Area of four walls of cube = 4 × side² .