The length, breadth and height of a room are 15m, 10m, 5m respectively. If the length breadth and height are increased by 10% each then work out the increase of the area of the 4 walls of the room.
Answers
Answer:
Given: The length of the room=15m
The breadth of the room =10m
The height of the room=10m
Percentage increment of the lengths=10%
Tip: if y is increased by x% then the new value of y is =y+
=y(
)In the above diagram the walls whose area has to be calculated is shown. ( they are numbered as 1,2,3,4,5)
The total summation of these areas before any change is
=
=300+200+150
=650
The length, breadth, height after increment will be:
length=16.5 m
breadth=11m
height=11m
Therefore, the new sum of the five areas is
=
=363+242+181.5
=786.5
Therefore, the change in the area is
=786.5-650
=136.5
Percentage change is
= 21%
Q. 19The length, breadAnswerGiven: The length of the room=15mThe breadth of the room =10mThe height of the room=10mPercentage increment of the lengths=10%
Q. 19The length, breadAnswerGiven: The length of the room=15mThe breadth of the room =10mThe height of the room=10mPercentage increment of the lengths=10%Tip: if y is increased by x% then the new value of y is
Q. 19The length, breadAnswerGiven: The length of the room=15mThe breadth of the room =10mThe height of the room=10mPercentage increment of the lengths=10%Tip: if y is increased by x% then the new value of y is ength, breadth, height after increment will be: