Math, asked by neilgomes, 8 months ago

The length, breadth and height of a room are 30 m, 25 m, and 20 m, respectively. Find the longest tape which can measure the three dimensions of the room exactly.

Answers

Answered by annamaryjoseph977
4

Answer:

hcf of 30 25 and 20

30= 5*3*2

25=5*5

20=2*2*5

therefor hcf of 30m 25m and 20m is 5m

the longest tape which can measure the three dimensions of the room exactly  is 5m

Step-by-step explanation:

Answered by Anonymous
0

➪ \sf \red{Answer:-}

 \huge{ ➫} \tt GIVEN:-

length \: of \: room \:  = 7m25cm = 725cm \\ breadth \: of \: room \:  = 9m25cm = 925cm \\ height \: of \: room \:  = 8m25cm = 825cm

\huge ➫ \sf FIND:-

now \: we \: find \: HCF \: of \: 725,925 \: and \: 825

{\huge ➫  {\mathfrak{Solution:-}}}

725 = 5 \times 5 \times29 \\ 925 = 5 \times 5 \times 37 \\ 825 = 3 \times 5 \times 5 \times 11 \\  \\ so, \: heighest \: common \: factor \: is \: 5 \times 5 = 25 \\ therefore \: HCF \: of \: 725,925,825 \: is \: 25. \\  \therefore 25m is \:  the  \: longest \:  tape \:  measure \:  which  \: can  \: measure \:  all  \: the  \: dimensions.

so, \: answer \: is \:  \boxed{ \mathfrak{ 25m}}

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