The length, breadth and height of a room are 3m, 4m and 5m. Find the length of the longest rod that can be placed in the room.
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Answered by
7
We need to find the longest diagonal of cuboid = √ 5 ² + 4 ² + 3³ = √ 50
= 5 √ 2 m.
= 5 √ 2 m.
Answered by
5
the longest that can be placed in the room is the diagonal.
given length, breadth and height=3,4,5m
so diagonal=√l×l+b×b+h×h
=√5×5+4×4+3×3
√25+16+9
√50
7.09 m ( approximately)
given length, breadth and height=3,4,5m
so diagonal=√l×l+b×b+h×h
=√5×5+4×4+3×3
√25+16+9
√50
7.09 m ( approximately)
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