Question

The length breadth and height of a room are 4m, 3m, 2.5 m respectively . If room has one door of dimension 2m by 1m and two windows of dimension 1.5m by 1m. Find the cost of distempering its walls at the rate of rupees 5 per square meter​

Answer 1

Answer:

Answer

Total surface area of the room=2(lh+lb+hb)m

2

=2[9×6.5+9×8+8×6.5]m

2

=365m

2

Area of the door =l×b=2×1.5=3m

2

Area of the windows=l×b=1.5×1=1.5m

2

∴ Surface area of walls=TSA of room −Area of door−Area of windows

=365−3−1.5=360.5m

2

Cost of whitewashing per square meter=Rs. 6.40

∴ Cost of whitewashing the walls=Rs. 6.40×360.5

=Rs. 2307.2.

Answer 2

Step-by-step explanation:

Total surface area of the room=2(lh+lb+hb)m

2

=2[9×6.5+9×8+8×6.5]m

2

=365m

2

Area of the door =l×b=2×1.5=3m

2

Area of the windows=l×b=1.5×1=1.5m

2

∴ Surface area of walls=TSA of room −Area of door−Area of windows

=365−3−1.5=360.5m

2

Cost of whitewashing per square meter=Rs. 6.40

∴ Cost of whitewashing the walls=Rs. 6.40×360.5

=Rs. 2307.2.