Question

the length ,breadth and height of a room are 5 , 4 and 3m respectively find the cost of white washing the walls of the room and the ceiling at the rate of Rs. 7.50 per meter square

Answer 1

Answer:

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The cost of whitewashing the walls of the room and ceiling is ₹ 555

Step-by-step explanation:

Solution:

Given:

The length, breadth, and height of a room are 5 m, 4 m, and 3 m respectively.

Since the four walls and ceiling are to be whitewashed so, it has 5 faces only, excluding the base.

Hence, the area of the room to be whitewashed can be obtained by adding the area of the ceiling to the lateral surface area of the cuboidal room.

Lateral surface area of cuboid = 2(l + b)h

The length, breadth and height of a room are 5 m, 4 m, and 3 m respectively. Find the cost of white washing the walls of the room and ceiling at the rate of ₹7.50 per m².

The cost of whitewashing the walls of the room and ceiling will be equal to the area of the room to be whitewashed multiplied by the rate of the whitewashing per m2.

Length, l = 5 m

Breadth, b = 4 m

Height, h = 3 m

Surface area of 5 faces = Area of the 4 walls and ceiling = lb + 2(l + b)h

lb + 2(l + b)h = (5 m × 4 m) + 2 × (5 m + 4 m) × 3 m

= 20 m² + 2 × 9 m × 3 m

= 20 m² + 54 m2

= 74 m²

The cost of whitewashing the walls of the room and ceiling = Rate × Area

= ₹ 7.50 / m² × 74 m2

= ₹ 555

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Answer 2

Answer:

The cost of whitewashing the walls of the room and ceiling = ₹ 555

Step-by-step explanation:

The length, breadth, and height of a room are 5 m, 4 m, and 3 m respectively.

Length, l = 5 m

Breadth, b = 4 m

Height, h = 3 m

Surface area of 5 faces = Area of the 4 walls and ceiling = lb + 2(l + b)h

lb + 2(l + b)h = (5 m × 4 m) + 2 × (5 m + 4 m) × 3 m

= 20 m² + 2 × 9 m × 3 m

= 20 m² + 54 m2

= 74 m²

The cost of whitewashing the walls of the room and ceiling = Rate × Area

= ₹ 7.50 / m² × 74 m2

= ₹ 555