Question

The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find lateral surface are of the room. *​

Answer 1

Given :

The length, breadth and height of a room are 5 m, 4 m and 3 m respectively.

To Find :

Lateral surface area of the room. 

Solution :

Analysis :

We know that a room in always in the form of a cuboid. So by using the formula of lateral surface area of the cuboid we can find the lateral surface area of the room.

Required Formula :

Lateral surface area = 2h(l + b)

where,

• h = height
• l = length
• b = breadth

Explanation :

We know that if we are given the length, breadth and height of a cuboidal room and is asked to find its lateral surface area then our required formula is,

Lateral surface area = 2h(l + b)

where,

• h = 3 m
• l = 5 m
• b = 4 m

Using the required formula and substituting the required values,

⇒ Lateral surface area = 2h(l + b)

⇒ Lateral surface area = 2 × 3(5 + 4)

⇒ Lateral surface area = 2 × 3(9)

⇒ Lateral surface area = 6(9)

⇒ Lateral surface area = 6 × 9

⇒ Lateral surface area = 54

∴ Lateral surface area = 54 m².

The lateral surface area of the room is 54 m².

Explore More :

• Total surface area of cuboid = 2(lb + bh + lh)

• Volume of cuboid = l × b × h

• Total surface area of cube = 6a²

• Lateral surface area of cube = 4a²

• Volume of cube = a³

where,

• l = Length
• b = Breadth
• h = Height
• a = Side of cube

Answer 2

Given :

The length, breadth and height of a room are 5 m, 4 m and 3 m respectively.

To Find :

Lateral surface area of the room. 

Solution :

Analysis :

We know that a room in always in the form of a cuboid. So by using the formula of lateral surface area of the cuboid we can find the lateral surface area of the room.

Required Formula :

Lateral surface area = 2h(l + b)

where,

h = height

l = length

b = breadth

Explanation :

We know that if we are given the length, breadth and height of a cuboidal room and is asked to find its lateral surface area then our required formula is,

Lateral surface area = 2h(l + b)

where,

h = 3 m

l = 5 m

b = 4 m

Using the required formula and substituting the required values,

⇒ Lateral surface area = 2h(l + b)

⇒ Lateral surface area = 2 × 3(5 + 4)

⇒ Lateral surface area = 2 × 3(9)

⇒ Lateral surface area = 6(9)

⇒ Lateral surface area = 6 × 9

⇒ Lateral surface area = 54