Question

The length Breadth and height of
a room are 5m, 4 m and
3 m respectively. Find the
cost of while washing the
walls of the room and
the ceiling at the rate of
₹ 7.50 m²​

Answer 1

HERE IS THE PROCESS DEAR..

length of the room = 5m

bradth of the room= 4m

height of the room=3m

so,

area of ceilling = length ×breadth

= 5m×4m = 20m²

and

the area of four walls =2(length+breadth)height

= 2(4+5)3m²

= 6×9m²= 54m²

so,

the total area of walls and ceiling = 20m²+54m²

= 74m²

now,

if cost of white washing of 1m² = 7.50rupees so, cost of white washing of 74m² = 7.50× 74

= 555rupees

.

.

.

.

.

.

thankyou ❤

ＬＯＶＥＹＯＵＲＳＥＬＦ

plz mark me as brainliest!......

Answer 2

AnswEr :

⋆ Refrence of Image is in the Diagram :

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\put(8,5.5){5 m}\put(4,6.3){4 m}\put(11.2,7.5){3 m}\end{picture}$

$\rule{150}{1}$

☯⠀$\underline{\textsf{Area Required for White Washing :}}$

$:\implies\tt Area = CSA + Ceiling\:Area\\\\\\:\implies\tt Area = \lbrack2h(l + b) \rbrack + (l \times b)\\\\\\:\implies\tt Area = \lbrack2 \times 3(5 + 4)\rbrack + (5 \times 4)\\\\\\:\implies\tt Area = \lbrack6 \times 9 \rbrack + 20\\\\\\:\implies\tt Area =(54 + 20) \:m^2\\\\\\:\implies\tt Area =74 \:m^2$

$\rule{200}{2}$

☯⠀$\underline{\textsf{Cost of White Washing :}}$

$\dashrightarrow\tt\:\:Cost=Area \times Rate\\\\\\\dashrightarrow\tt\:\:Cost=74\:\cancel{m^2} \times Rs\:7.50\:\cancel{m^{-2}}\\\\\\\dashrightarrow\tt\:\:Cost=74 \times Rs\:7.50\\\\\\\dashrightarrow\:\:\underline{\boxed{\red{\tt Cost = Rs.\:555}}}$

⠀

$\therefore\:\underline{\textsf{Cost of white washing is \textbf{Rs. 555}}}$