Question

The length,breadth and height of a room are 5m,4m,3m respectively.Find the cost of white washing the walls of the room and the ceiling at the rate of Rs7.50 per m².
plss answer it fast..with well explanation...if needed u can also add an attachment...but plss explain it properly..​

Answer 1

Step-by-step explanation:

given that,

length = 5 m 

breadth = 4 m 

height = 3 m 

area of wall = 2h (L+  b)

                     = 2 ×3 (4 +5 )

                     = 6×9

                     = 54 sq m

area of cieling = l×b

                         = 5 ×4 

                        = 20 sq m

total area= area of cieling + area of cieling 

               = 54 + 20 sq m

               = 74 sq m

cost of white washing for 1 sq m = rs 50

             so for 74 sq m = 50×74 sq m

                                        = rs 3700

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The length,breadth and height of a room are 5m,4m and 3m respectively.The celling at the rate of Rs.7.50/m².

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The cost of the white washing the walls of the room.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

We know that formula of the surface area of the 4 walls and celling of the room;

$\boxed{\sf{2[length+breadth]\times height+length\times breadth}}}}}$

We have;

• Length of a room = 5m
• Breadth of a room = 4m
• Height of a room = 3m

A/q

$\longrightarrow\sf{2[5+4]\times 3+5\times 4}\\\\\longrightarrow\sf{2[9]\times 3+20}\\\\\longrightarrow\sf{18\times 3+20}\\\\\longrightarrow\sf{54+20}\\\\\longrightarrow\sf{\pink{74m^{2} }}$

Now;

$\longrightarrow\sf{1m^{2} =Rs.7.50}\\\\\longrightarrow\sf{74m^{2} =Rs.(7.50\times 74)}\\\\\longrightarrow\sf{\orange{Cost\:of\:white\:washing\:of\:the\:room=Rs.555}}$