Question

. The length, breadth and height of a room are 5m, 4m and 3m respectively. Find the area

of the walls of the room​

Answer 1

$\sf{length} = 5m$

$\sf{breadth = 4m}$

$\sf{height = 3m}$

$\sf{area \: of \: walls \: = csa }$

$\red{ \boxed{ \sf{csa \: of \: cuboid = 2h( l+ b)}}}$

$: ⟹ \: \: \: \: \: 2 \times 3(5 + 4)$

$\: \: \: \: \: : ⟹ \: \: \: \: \: 6 \times 9$

$\: \: \: \: \: \: \: \: \: \: \: : ⟹ \sf{54 {m}^{2} }$

$\sf\orange{please \: mark \: as \: brainliest............}$

Answer 2

Answer :-

Area of 4 walls = 54 sq. m.

Explanation :-

Given :

• Length of room = 5m.
• Breadth of room = 4m.
• Height of room = 3m.

To Find :

• Area of 4 walls of a room.

Solution :

Area of 4 walls of a room = 2(l + b)h.

Substitute the values.

➠ Area of 4 walls = 2(5 + 4)3.

➠ Area of 4 walls = (2)(9)(3).

➠ Area of 4 walls = (18)(3).

➠ Area of 4 walls = 54 sq. m.

Therefore, Area of 4 walls = 54 sq. m.

Extra Shots :-

• T.S.A. of Cuboid = 2(lb + bh + hl).
• C.S.A. of Cuboid = 2(l + b)h.
• Volume of Cuboid = l × b × h.