Question

the Length breadth and height of a room are 5m. 4m and 3m respectively. find the cost of white washing of the walls of the room and the ceiling at the rate of Rs.7.50 per m².​

Answer 1

Answer:

Total Surface Area to be white washed

Total Surface Area to be white washed=LTA+ Area of the base

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m 2

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m 2 =74m

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m 2 =74m 2

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m 2 =74m 2

Total Surface Area to be white washed=LTA+ Area of the base=2(l+b)h+lb=2(5+4)×3+5×4m 2 =74m 2 Cost of white washing =Rs.(74×7.50)=Rs.555

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Answer 2

Answer:

The cost of white washing of the walls of the room and the ceiling is Rs 555.

Step-by-step explanation:

Given:-

         The Length  of a room are 5m.

          The  breadth  of a room are 4m

          and  The height  of a room are 3m .

Formula used:-

            Total Surface Area to be white washed =LTA+ Area of the base

               LTA=$2(l+b)h$

            Area of the base$=lb$

Total Surface Area to be white washed=

                          $2(l+b)h+lb\\ \\ =2(5+4)\cdot 3+5\cdot 4m ^2 \\ \\ =74m ^2$

The rate of  white washing of the walls of the room and the ceiling is Rs.7.50 per m².​

Cost of white washing =$Rs.(74\cdot 7.50)=Rs.555$