The length, breadth and height of a room are 5m,4m and 3m respectively.find the cost of white washing the walls and the ceiling at the rate of ₹7.50 per m^.
Answers
Answer:
Step-by-step explanation
Length=5m
Breadth=4m
Height=3m
Lateral Surface Area= 2h (l+b)
=2×3(5+4)m sq.
=6×(9)m sq.
=54m sq.
Area of the ceiling= l×b
=5×4
=20m sq.
Total area needed to be whitewashed= 54 + 20 m sq.
=74m sq.
Cost of whitewashing 1 m sq.= Rs. 7.50
Cost of whitewashing 74m sq.= 74 × 7.50
= Rs. 555.0
Therefore answer : Rs.555
Hope this helped you
✬ Cost = Rs 555 ✬
Step-by-step explanation:
Given:
- Length (l) , breadth (b) and height (h) of room are 5m ,4m and 3m respectively.
- Cost of white washing is Rs 7.50 m².
To Find:
- What is the cost of white washing the walls and ceiling ?
Solution: As we know that the formula for area of four walls of room is
★ Area of four walls of room = 2h ( l + b) sq units ★
Area of four walls = 2 3 ( 5 + 4 ) m²
( 6 9 ) m²
54 m²
So, the area of four walls of the room is 54 m².
Formula for area of ceiling of room is -
★ Area of ceiling = ( L x B ) sq units. ★
- Since, the ceiling is in rectangular form.
Area of ceiling = ( 5 x 4 ) m²
20 m².
➱ Area of whole room = Area ( Four walls + Ceiling )
➱ Area of whole room = ( 54 + 20 ) m² = 74 m².
• Cost of white washing for 1 m² = Rs 7.50
∴ Cost of white washing for 74 m² = 7.50 x 74 = Rs 555 .
Hence, the cost of white washing the room at 7.50 /m² is Rs 555.
____________________
➼ Or, simple we can find the area of whole room by using this formula
★ 2h ( l + b ) + l x b ★
➟ { 2 3 ( 5 + 4 ) + 5 4 } m²
➟ { 6 9 + 20 } m²
➟ { 54 + 20 } m²
➟ 72 m²