Question

The length, breadth and height of a room are 7 m 25 cm, 9 m 25 cm
and 8 m 25 cm respectively. Determine the length of the largest tape
which can measure the three dimensions of the room exactly.

Answer 1

Given :

• Length of the room = 7m 25cm.

• Breadth of the room = 9m 25cm.

• Height of the room = 8m 25cm.

To find :

• The length of the largest tape which can measure the three dimensions of the room exactly =?

Step-by-step explanation :

Length of the room = 7m 25cm Or 725 cm.

Breadth of the room = 9m 25cm Or 925 cm.

Height of the room = 8m 25cm Or 825 cm.

We have to find the length of the largest tape which can measure the three dimensions of the room exactly. So, HCF ( Highest Common Factor) of the given dimensions.

HCF of 725, 925 and 825 :-

725 = 5 × 5 × 29

925 = 5 × 5 × 37

825 = 3 × 5 × 5 × 11

•°• HCF = 5 × 5 = 25

Therefore, the length of the largest tape

which can measure the three dimensions of the room exactly = 25 cm.

Answer 2

GIVEN :

• Length of the room = 7m 25Cm
• Breadth of the room = 9m 25Cm
• Height of the room = 8m 25Cm

TO FIND :

• The length length of the tape which can be used to measure the three dimensions of the room exactly = ?

STEP - BY - STEP EXPLANATION :

→ Length = 7m 25Cm (GIVEN)

→ Breadth = 9m 25Cm (GIVEN)

→ Height = 8m 25Cm (GIVEN)

Now, we'll have to find the largest tape which can measure all the three dimensions of the room , so we'll now find the (HCF) (Highest common factor)

(NOTE :------ we will have to change 7m 25cm, 9m 25Cm and 8m 25Cm into cm form )

=> 725Cm = 5 × 5 × 29

=> 925Cm = 5 × 5 × 37

=> 825Cm = 3 × 5 × 5 × 11

=> HCF = 5 × 5 = 25

Hence, HCF (Highest common factor) of 725, 925 and 825 = 5Cm