Math, asked by piyushgavali4455, 9 months ago

The length, breadth and height of a room are 725 cm, 925 cm and 825 cm respectively. Determine the length of the largest tape which can measure the three dimensions of the room exactly.


Answers

Answered by BrainlyRaaz
25

Given :

  • Length of the room = 725 cm.

  • Breadth of the room = 925 cm.

  • Height of the room = 825 cm.

To find :

  • The length of the largest tape which can measure the three dimensions of the room exactly =?

Step-by-step explanation :

Length of the room = 725 cm.

Breadth of the room = 925 cm.

Height of the room = 825 cm.

We have to find the length of the largest tape which can measure the three dimensions of the room exactly. So, HCF ( Highest Common Factor) of the given dimensions.

HCF of 725, 925 and 825 :-

➮ 725 = 5 × 5 × 29

➮ 925 = 5 × 5 × 37

➮ 825 = 3 × 5 × 5 × 11

•°• HCF = 5 × 5 = 25

Therefore, the length of the largest tape which can measure the three dimensions of the room exactly = 25 cm.

Answered by Anonymous
31

\rule{200}3

Given :-

  • Length of the room = 725 cm.

  • Breadth of the room = 925 cm.

  • Height of the room = 825 cm.

\rule{200}3

To find :-

Largest tape to measure length, Breadth and height.

\rule{200}3

Step by step Explaination :-

\therefore largest measuring tape = HCF of 725, 925, 825

HCF of 725, 925, 825

\begin{array}{r | l}</p><p></p><p>5 &amp; 725 \\</p><p></p><p>\cline{2-2} 5 &amp; 145 \\</p><p></p><p>\cline{2-2} 29 &amp; 29 \\</p><p></p><p></p><p>\cline{2-2} &amp; 1</p><p></p><p>\end{array}

\begin{array}{r | l}</p><p></p><p>5 &amp; 925 \\</p><p></p><p>\cline{2-2} 5 &amp; 185 \\</p><p></p><p>\cline{2-2} 37 &amp; 37 \\</p><p></p><p></p><p>\cline{2-2} &amp; 1</p><p></p><p>\end{array}

\begin{array}{r | l}</p><p></p><p>3 &amp; 825 \\</p><p></p><p>\cline{2-2} 5 &amp; 275 \\</p><p></p><p>\cline{2-2} 5 &amp; 55 \\</p><p></p><p>\cline{2-2} 11 &amp; 11 \\</p><p></p><p>\cline{2-2} &amp; 1</p><p></p><p>\end{array}

\rule{200}3

Therefore,

  • 725 = 5 × 5 × 29

  • 925 = 5 × 5 × 37

  • 825 = 3 × 5 × 5 × 11

\therefore HCF = 5 × 5 = 25

Therefore, the length of the largest which can measure the three dimensions of room exactly = 25 cm.

\rule{200}3


BrainlyRaaz: Awesome ❤️
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